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The microcurrent through the electrode in a delicate circuit
[#permalink]
20 Nov 2017, 11:43

1

1

Question Stats:

The microcurrent through the electrode in a delicate circuit is usually held constant at \(3.6*10^{(-8)}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?

A. \(3.6 * 10^{(-8000)}\)

B. \(3.6 * 10^{(-24)}\)

C. \(3.6 * 10^{(-11)}\)

D. \(3.6 * 10^{(-5)}\)

E. \(3.6 * 10^{(-\frac{8}{3})}\)

Kudos for correct solution.

A. \(3.6 * 10^{(-8000)}\)

B. \(3.6 * 10^{(-24)}\)

C. \(3.6 * 10^{(-11)}\)

D. \(3.6 * 10^{(-5)}\)

E. \(3.6 * 10^{(-\frac{8}{3})}\)

Kudos for correct solution.

Re: The microcurrent through the electrode in a delicate circuit
[#permalink]
14 Jan 2018, 02:39

1

The microcurrent is usually held at 3.6*10^{(-8)} however this has to be reduced by 1000 times or 10^3

If we multiply 3.6*10^{(-8)} by 10^3 we get 3.6*10^{(-5)} which is bigger than the original number not smaller

so we have to multiply 3.6*10^{(-8)} by 10^{(-3)}

(c)

_________________

If we multiply 3.6*10^{(-8)} by 10^3 we get 3.6*10^{(-5)} which is bigger than the original number not smaller

so we have to multiply 3.6*10^{(-8)} by 10^{(-3)}

(c)

_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos

Re: The microcurrent through the electrode in a delicate circuit
[#permalink]
25 Jan 2018, 07:08

1

Just divide the given equation 3.6*(1e-8) by 1.000 (or 10³) to get 3.6*(1e-11).

-> Answer C is correct

-> Answer C is correct

The microcurrent through the electrode in a delicate circuit
[#permalink]
21 Nov 2018, 08:50

Expert Reply

The microcurrent through the electrode in a delicate circuit is usually held constant at \(3.6 * 10^{-8}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?

A. \(3.6*10^{-8000}\)

B. \(3.6*10^{-24}\)

C. \(3.6*10^{-11}\)

D. \(3.6*10^{-5}\)

E. \(3.6*10^{\frac{-8}{3}}\)

_________________

A. \(3.6*10^{-8000}\)

B. \(3.6*10^{-24}\)

C. \(3.6*10^{-11}\)

D. \(3.6*10^{-5}\)

E. \(3.6*10^{\frac{-8}{3}}\)

_________________

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Re: The microcurrent through the electrode in a delicate circuit
[#permalink]
23 Nov 2018, 13:43

Carcass wrote:

The microcurrent through the electrode in a delicate circuit is usually held constant at \(3.6 * 10^{-8}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?

A. \(3.6*10^{-8000}\)

B. \(3.6*10^{-24}\)

C. \(3.6*10^{-11}\)

D. \(3.6*10^{-5}\)

E. \(3.6*10^{\frac{-8}{3}}\)

A. \(3.6*10^{-8000}\)

B. \(3.6*10^{-24}\)

C. \(3.6*10^{-11}\)

D. \(3.6*10^{-5}\)

E. \(3.6*10^{\frac{-8}{3}}\)

1,000 times smaller means we divide it by 1,000 which is basically 10^3

So (3.6 * 10^-8)/(10^3) = 3.6 * 10^(-8 -3) = 3.6 * 10^-11

Answer choice C

Re: The microcurrent through the electrode in a delicate circuit
[#permalink]
27 Nov 2018, 06:52

thanks

Re: The microcurrent through the electrode in a delicate circuit
[#permalink]
18 Nov 2019, 09:01

1

Expert Reply

Bunuel wrote:

The microcurrent through the electrode in a delicate circuit is usually held constant at \(3.6*10^{(-8)}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?

A. \(3.6 * 10^{(-8000)}\)

B. \(3.6 * 10^{(-24)}\)

C. \(3.6 * 10^{(-11)}\)

D. \(3.6 * 10^{(-5)}\)

E. \(3.6 * 10^{(-\frac{8}{3})}\)

A. \(3.6 * 10^{(-8000)}\)

B. \(3.6 * 10^{(-24)}\)

C. \(3.6 * 10^{(-11)}\)

D. \(3.6 * 10^{(-5)}\)

E. \(3.6 * 10^{(-\frac{8}{3})}\)

Key concept #1: If X is 1000 times smaller than Y, we can write: X = Y/1000

Key concept #2: \(\frac{ab}{c}=(a)(\frac{b}{c})\)

So, the measure of the resulting current = \(\frac{3.6*10^{(-8)}}{1000}\)

Rewrite as: \(\frac{3.6*10^{(-8)}}{10^3}\)

Use Concept #2 to rewrite as: \((3.6)\frac{10^{(-8)}}{10^3}\)

Apply Quotient Law for exponents to get: \((3.6)(10^{(-8-3)})\)

Simplify: \((3.6)(10^{(-11)})\)

Answer: C

Cheers,

Brent

_________________

Re: The microcurrent through the electrode in a delicate circuit
[#permalink]
16 Aug 2021, 21:20

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